Satisfy the wave equation
use dS/df = 0. the "least action" principle, or it should be 'stationary action' (minimum or maximum of the action).
substitute in S = integral of L over time
evaluate by using, I'm guessing, this:
Plug in the Kinetic and Potential energies, T - V, and set the integral to zero. Say that the integrand must equal zero 'cause... energies are non-negative, I guess.
Then let v squared equal Tau over roe.
Basically, copy the example 1.4 solved for the two dimensional string vibration. I didn't do anything different except change the spatial derivative into a gradient.
... so I must've done something wrong LOL.
I didn't use functional derivatives. Well, I guess I used a bastardized form (which might be incorrect) of a result we showed previously with functional derivatives.


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